Find a quadratic equation whose roots are
3-

x² - 6x + 6 = 0

Step-by-step explanation:

Given the roots are x = 3 - and x = 3 + , then the corresponding factors are

(x - (3 - ) ) and (x - (3 + ) ), that is

(x - 3 + ) and (x - 3 - )

The equation is then the product of the factors

(x - 3 + )(x - 3 - ) = 0

(x - 3)² - ( )² = 0

x² - 6x + 9 - 3 = 0

x² - 6x + 6 = 0

6e14 is the answer.