An office manager booked 61 airline tickets. He booked 8 more tickets on Airlines A than Airlines B. On Airlines C, he booked 5 more than twice as many tickets as on Airlines B. How many tickets did he book on each airline?

B = 12

A =  20

C =  29

Step-by-step explanation:

A = tickets on airline A

B = A-8

C = 2B +5

Total = 61

A + B+ C = 61

Taking B = A -8 and writing in terms of A  

A = B+8

Replacing A and C in the equation A + B+ C = 61

( B+8) + B + 2B +5  = 61

Combining like terms

4B +13 = 61

Subtract 13 from each side

4B =13-13 = 61-13

4B =48

Divide by 4

4B /4 = 48/4

B = 12

A = B +8 = 12+8 = 20

C = 2B +5 = 2*12+5 = 24+5 = 29

the answer is 5636.7

a) 7x=7

step-by-step explanation: