A 32-inch piece of steel is cut into three pieces so that the second piece is twice as long as the first piece, and the third piece is two times more than seven times the length of the first piece. Find the lengths of the pieces.

first piece = 1.88in

second piece= 3.76in

third piece = 26.32in

32 = f + s + t

1st piece = f

2nd piece = s

3rd piece = t

what we know:

s = 2f

t = 2(7f)

32 = f + 2f + 2(7f)

32 = 3f +14f

32 = 17f

f = 1.88

now sub in:

f = 1.88

s = 3.76

t = 26.32

when you add these together you get 31.96, when you round up you get 32 which is the original piece of steel.

the answer is 2/54

step-by-step explanation:

answer4 to the second power is 16

and 4 to the third power is 64,