Struggling at 9b) please help

b = 7, c = -3 and a = 1

Step-by-step explanation:

So I'm assuming you know the quadratic formula, x=-b +- root (b^2-4ac)/2a

so knowing this, it is given that b^2 - 4ac = 61

it is also given 2a = 2 (the bottom of the fraction) which means a =1

and the -b = -7 (the start of the expression), which means b = 7

now we have b = 7, and a = 1

now we can sub it into b^2 - 4 x a x c = 61

b^2 is 7 x 7 = 49

4 x a x c = 4c

so we have 49-4c=61

-4c = 61-49

-4c = 12

c = -3

therefore we have b = 7, c = -3 and a = 1

jeff jeff

step-by-step explanation: