Clara cycles at a constant speed of 5 meters per second from west to east along a path. She passes a road sign during her ride. If t represents the number of seconds since Clara was 13 meters east of the road sign, write an expression to represent Clara's distance east of the road sign. Distance Clara is East of the road sign = meters.

The distance Clara is from East of the road sign  is given by the expression:

d  =  13  +  5t

The speed at which Clara was cycling, v = 5 m/s

The time since Clara was 13 meters east of the road sign = t

The initial distance of Clara,

Distance = Speed x Time

Clara's distance at t seconds,

Clara's distance east of the road sign = Clara's initial distance + Clara's distance at t seconds

Therefore, the distance Clara is from East of the road sign  is given by the expression:

d  =  13  +  5t

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d(t) = 5m/s*t + 13m

Step-by-step explanation:

We have the relationship:

Distance = time*speed.

We know that the speed is 5 m/s and that t represents time in seconds.

then:

distance = 5m/s*t

We know that at t = 0s, Clara was at 13m pass the sign, then we have a y-intercept of b = 13m

So we can write the distance of the road sign as a linear equation:

d(t) = 5m/s*t + 13m

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x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.