If the sum of four consecutive numbers is 1770, what is the last one?

444

Step-by-step explanation:

So we know that the sum of four consecutive numbers is 1770.

Let the first number be n,

Then the second number must be (n+1), followed by (n+2) and (n+3).

They sum to 1770, so:

Combine like terms:

Subtract 6 from both sides:

Divide both sides by 4:

So, the first number is 441.

So our sequence is 441, 442, 443, and 444.

Thus, our last number is 444.

And we're done!

v: l•w•h÷2.

v: 20•6•8 ÷2

v: 960÷2

v: 480

a

step-by-step explanation: