The perimeter of a rectangle is 60 meters. What are the possible lengths of any of the rectangle’s sides if its area exceeds 216 square meters? (12, 18) [12, 18)

the possible sides of a rectangle is 12,  18

Step-by-step explanation:

given:

The perimeter of a rectangle is 60 meters

find:

What are the possible lengths of any of the rectangle’s sides if its area exceeds 216 square meters?

Perimeter (P) = 60 = 2L + 2W ------eq.1

Area (A) = 216 = L x W  ---------------eq.2

you can use any of the two equations to to get L or W

say we use the Area = 216 = L x W

L = 216

       W

plugin values to eq.1

60 = 2L + 2W

60 = 2( 216 ) + 2W

              W

multiply both sides by W

60W = 2(216) + 2W²

60W = 432 + 2W²

rearrange the equation into a quadratic equation:

2W² - 60W + 432 = 0

now, solve for W

       - (-60) ±

W = --------------------------------------------

                        2 x 2

W = 60 ± 12

             4

W = 12

W = 18

therefore,

the possible sides of a rectangle is 12,  18

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

hdjd

step-by-step explanation: