Points (2,−1), (−2,7), (1,−2), (0,−1), and (4,7) lie on the graph of a quadratic function. a. What is the axis of symmetry of the graph? b. What is the vertex? c. What is the y-intercept? d. Over what interval does the function increase?

a) The Axis of Symmetry is X = 1

b) The Vertex is (1,-2)

c) X=0 at Y = -1

d) y = (x-1)^2 - 2

Step-by-step explanation:

a) This is where the graph can be divided into 2 equal parts. Since this is a parabola it is located at the origin.

b) The vertex is the lowest or highest part of the graph. With parabolas it is also the origin.

c)The y-intercept is the point where the graph passes through the y-axis or where x = 0.

d)If you look at the points (0,-1) and (2,1). They are both left/right one, up one from the origin or (1,-2). This means it is a regular y=x^2 parabola, just moved over. If it was up two or three (etc) it would be up two or three, respectfully.

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.