A rectangular storage container with an open top has a volume of 20 3 . The length of its base is twice its width. Material for the base costs $20 per square meter; material for the sides costs $8 per square meter. Express the cost of materials as a function of the width of the base.

Correct question is;

A rectangular storage container with an open top has a volume of 20 m³. The length of its base is twice its width. Material for the base costs $20 per square meter; material for the sides costs $8 per square meter. Express the cost of materials as a function of the width of the base.

C = 40W² + 480/W

Step-by-step explanation:

We are given;

Volume; V = 20 m³

Length of base is L

Width of base is W

We are told L = 2W

Formula for volume of a cuboid = LWH

Thus;

20 = 2W × W × H

20 = 2W²H

H = 10/W²

Now, we are given cost of materials for base and sides.

Formula for base area = LW = 2W²

Formula for side areas = 2(LH) + 2(WH) = 2(2WH) + 2WH = 6WH = 6W(10/W²) = 60/W

Cost per Sq.m of base = $20.

Thus, base cost = 20(2W²) = 40W²

Cost per Sq.m of sides = 8(60/W)

Thus,sides cost = 480/W

Total cost of sides and base is;

C = 40W² + 480/W

24

step-by-step explanation:

the graph shows 30% of students walk. 80 students were questioned, so the number that said they walk is

30% × 80 = 0.30 × 80 = 24

answer: the distance

step-by-step explanation:

to calculate the distance d of a line segment with endpoints (x1, y1) and (x2, y2) use the formula d (x2 x1)2 (y2 y1)2. to calculate the midpoint of a line segment with endpoints (x1, y1) and (x2, y2) use the formula