Euler's formula V -E + F =2, relates the number of vertices, V, the number of edges E, and the number of faces F of a polyhedron. Solve Euler's formula for F (the variables ARE case sensitive) How many faces does a polyhedron with 8 vertices and 12 edges have?

F = 6

Step-by-step explanation:

Given:

Euler's formula V - E + F =2

Where,

V = vertices

E = number of edges

F = number of faces of a polyhedron

Solve Euler's formula for F

V - E + F = 2

Subtract V and add E to both sides

F = 2 - V + E

How many faces does a polyhedron with 8 vertices and 12 edges have

When V = 8 and E = 12

F = 2 - V + E

= 2 - 8 + 12

= 6

F = 6

Therefore, a polyhedron with 8 vertices and 12 edges have 6 faces

i will take them

step-by-step explanation:

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