A telephone line hangs between two poles 14 m apart in the shape of the catenary y = 23 cosh(x/23) − 18, where x and y are measured in meters. (a) Find the slope of this curve where it meets the right pole. (Round your answer to four decimal places.) .3091 (b) Find the angle θ between the line and the pole. (Round your answer to two decimal places.)

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

(x, y)→(x − 8, y − 7)

step-by-step explanation:

enjoy!

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)

127

whether it's diameter, or radius, i believe if i remember correctly from school, every amount has to always add up to 180. so if you take 53, and starting adding, long story short, taking 127 and adding it to 53, gives you 180.