Mathematics, 19.09.2020 01:01 melissalopez12
The difference between differences of the y-values in a quadratic function is 2. If two ordered pairs in that quadratic function were (2, 10) and (3, 16), what is the y-value of the ordered pair (4,y)?
Answers: 2
Mathematics, 21.06.2019 18:00
Write the fraction or mixed number and the decimal shown by the model
Answers: 2
Mathematics, 21.06.2019 22:00
Worth 100 points need the answers asap first row -x^2 2x^2 (x/2)^2 x^2 x is less than 2 x is greater than 2 x is less than or equal to 2 x is greater than or equal to 2 second row -5 -5/2 4 5 •2 is less than x& x is less than 4 •2 is less than or equal to x & x is less than or equal to 4 •2 is less than or equal to x& x is less than 4 •2 is less than x& x is less than or equal to 4
Answers: 1
Mathematics, 22.06.2019 00:00
Fill in the blank 1. a rhombus is a rectangle a) always b) sometimes c) never 2. a square is a quadrilateral a) always b) sometimes c) never 3. a trapezoid is a kite a) always b) sometimes c) never 4. a quadrilateral is a kite a) always b) sometimes c) never 5. a square is a rhombus a) always b) sometimes c) never 6. a parallelogram is a rectangle a) always b) sometimes c) never
Answers: 1
Mathematics, 22.06.2019 04:30
Problems and applications q5 four roommates are planning to spend the weekend in their dorm room watching old movies, and they are debating how many to watch. here is their willingness to pay for each film: willingness to pay (dollars) shen antonio dmitri jake first film 10 9 8 3 second film 8 7 6 2 third film 6 5 4 1 fourth film 4 3 2 0 fifth film 2 1 0 0 within the dorm room, the showing of a movie a public good. if it costs $12 to rent a movie, the roommates should rent movies in order to maximize the total surplus. suppose the roommates choose to rent the optimal number of movies you just indicated and then split the cost of renting equally. this means that each roommate will pay $ .
Answers: 2
The difference between differences of the y-values in a quadratic function is 2. If two ordered pair...
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