Quadrilateral abcd has coordinates a (3, -5), b (5, -2), c (10, -4), d (8, -7). quadrilateral abcd is a

ab = sqr root (5-3)^2 + (-2+5)^2 = sqr root 13
bc = sqr root(10-5)^2 + (-4+2)^2= sqr root 29
cd= sqr root(8-10)^2 + +4)^2 = sqr root 13
da = sqr root(3-8)^2 + (-5+7)^2 = sqr root 29

We are given the coordinates of a quadrilateral. IN this case, we are asked in the problem to determine the length of the sides. Through the distance formula square root of [(x2-x1)^2 + (y2-y1)]^2. in this case, there are two congruent sides opposite to each other. This quadrilateral could be a parallelogram. 

The answer is: a = about 63.59ft2 for 15