The lengths of the sides of a triangle are consecutive integers. If the perimeter of the triangle is 111, find the lengths of the sides.

we know

perimeter of triangle = sum of all sides

here lengths of sides are consecutive integers so

length  of three sides = x, (x+1) and (x+2)

now

Perimeter = 111

or,  x + (x+1) + (x+2) = 111

or 3x + 3 = 111

or 3x = 108

x = 36

x = 36

(x+1) = 36 + 1 = 37

(x+2)= 36 + 2 = 38

b. 24 mm

step-by-step explanation:

use the pythagorean theorem.

a^2 + b^2 = c^2

a^2 + 7^2 = 25^2

a^2 + 49 = 625

a^2 = 576

a = 24

answer: b. 24 mm

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,