Two balls are to be pulled from a vase that contains 7 red balls 9 green balls and 2 black balls. After the first ball Is drawn, it is not the replaced. What is the probability that two black balls are chosen from the vase?

Step-by-step explanation:

There are a total of 7 + 9 + 2 = 18 balls in the vase, therefore, when not replacing the first ball, there would be 18 · 17 = 306 ways to pull 2 balls. There are 2 ways to choose the first black ball and then 1 way to choose the second black ball so there are 2 · 1 = 2 ways to choose 2 black balls. Therefore, the probability is 2 / 306 = .

54/3 is 18 so 18 is your answer