Balloon A is released 5 feet above the ground. Balloon B is released at ground level. Both balloons rise at a constant rate. Which situation can you represent using an equation of the form y = kx? Explain.

The situation of balloon B

Step-by-step explanation:

Balloon A is released 5 feet above the ground and our ground level be 0 feet. Let k be the rate at which it rises and t the time it takes to rise. Its height y, above the ground after time x is y = kt + 5

For Balloon B since it is released at ground level at which ground level is taken as 0 feet, let t be the time it takes to rise above the ground and k the rate at which it rises above the ground. Its height y above the ground after tie x is y = kt

Since the expression for Balloon B is y = kt and the expression for Balloon A is y = kt + 5, only the situation of Balloon B can be expressed in the form y = kx.

This is because the rate of rise of Balloon B follows a direct proportionality while the rate of rise of Balloon follow a joint proportionality since it starts from a point other than ground level.

step-by-step explanation: a reaction is first order. if the initial reactant concentration is 0.0200 m, and 25.0 days later the concentration is 6.25 x 10-4 m, then its half-life is:

complete the steps to find the area of the trapezoid.

area of rectangle = 256   square units

area of triangle 1 = 24  square units

area of triangle 2 = 16  square units

area of triangle 3 =   96 square units

area of trapezoid = 120  square units

step-by-step explanation: