In a population of elderly war veterans, the probability that a veteran will have been exposed to agent orange (a militarized herbicide) and develop cancer is 0.35. The probability is 0.75 that a veteran exposed to agent orange will develop cancer. The average age of the veterans is 67 years old. What is the probability that a random veteran will have been exposed to agent orange

Probability that a random veteran will have been exposed to agent orange is 0.4667

Step-by-step explanation:

P(exposed to agent cancer and develop cancer) = 0.35

P(develop cancer given he is already exposed to agent orange) = 0.75

P(is exposed to agent cancer) = ?

P(A given B) = P(A and B)/P(B),

P(develop cancer | exposed to agent orange)  = P(develop cancer and exposed to agent orange)/P(exposed to agent orange)  

0.75 = 0.35/P(exposed to agent orange)  

P(exposed to agent orange) = 0.35/0.75

P(exposed to agent orange) = 0.4667

16.9 times 2.85

step-by-step explanation:

answer: 0

step-by-step explanation: the positive, like 5, + its opposite, like -5 would be 0

5+(-5)=0, or 5-5=0