TOPIC: similtaneous linear equations

p1 + 2q = 3,
p - 2q = 3

p = 3 ; q = 0

Step-by-step explanation:

In this linear pair of eqn. in 2 variables , they have a unique solution i.e. they will have only single solution . We know that

& also . So, we can also equate them as :-

(∵ Both the eqn. have 3 in their right hand side product )

Solving the eqn. gives,

Putting the value of q in any one of the linear eqn gives ,

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step-by-step explanation:

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)