Need help on geometry #3

see explanation

Step-by-step explanation:

∠ PQS + ∠SQR = ∠ PQR , substitute values

13x + 4 + 10x - 1 = 141 , that is

23x + 3 = 141 (subtract 3 from both sides )

23x = 138 ( divide both sides by 23 )

x = 6

Thus

∠ PQS = 13x + 4 = 13(6) + 4 = 78 + 4 = 82°

∠ SQR = 10x - 1 = 10(6) - 1 = 60 - 1 = 59°

10 b/c 5*2 =10

step-by-step explanation:

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)