You are given the equation (2x^ny^2)^m = 4x^6y^4. Find two positive integers, m and n, that make the equation true.

Step-by-step explanation:

Given

Required

Solve for m and n

Start by opening the bracket using laws of indices

Express 4 as 2²

Compare both sides of the equation, we have:

--- (1)

--- (1)

 ---- (2)

In (1)

2 cancels out on both sides; so, we have

In (2)

x cancels out on both sides; so, we have

Substitute 2 for m

Divide through 2

In (3)

y cancels out on both sides; so, we have

Divide through 2

x= 149. 24+7=31. 180-31=149

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