If the area of a rectangle 16s2t and the length is 8st2, what would the width of the rectangle, given that width is found by dividing area by length? simplify the answer.

Area = Length x Width
Substituting the given values:
16S^2 t = 8St^2 x Width
Manipulating for Width:
Width = 16S^2 t / 8St^2
Rewriting the squared terms in simplified form :
Width = 16 x S x S x t / 8 x S x t x t
Cancelling the like terms
Width = 16 x S / 8 x t
Cancelling the numeric terms :  

Width = 2S / t

Here for a good time of free question aha