One interpretation of a baseball player's batting average is as the empirical probability of getting a hit each time the player goes to bat. If a player with a batting average of 0.2560.256 bats 55 times in a game, and each at-bat is an independent event, what is the probability of the player getting at least on hit in the game

The probability of getting at least one hit in 5 games is 0.772

Step-by-step explanation:

The correct question is as follows;

One interpretation of a baseball player's batting average is as the empirical probability of gettig a hit each time the player goes to bat. If a player witt a batting average of 0.256 bats 5 times in a game, and each at-bat is an independent event, what is the probability of the player getting at least one hit in the game?

We proceed with the answer as follows;

Here, we want to calculate the probability of a player with a certain batting average getting at least one hit in a game if he bats 5 times

Mathematically, Probability of getting at least one hit in 5 games = 1 - Probability of getting no hit in 5 games

Let p = probability of getting hit in a game = 0.256

q = Probability of getting no hit in a game = 1-0.256 = 0.744

So the probability of getting no hits in 5 games will be 0.744^5 = 0.228

Thus, the probability of getting at least one hit in the 5 games = 1 - 0.228 = 0.772

binomial distribution

median= 2

range = 7-0 = 7

how to find median?

no. of term=28

median=(28+1)/2=14.5th term

the 14th and 15th term are 2, therefore the median is (2+2)/2 = 2

step-by-step explanation:

you can add the two numbers and divide the result by 2. or you can find the gap between the two numbers and add half of this to the smaller number.