There are 3 different mathematics courses, 3 different science courses, and 5 different history courses. If a student must take one of each, how many different ways can this be done?

45 ways

Step-by-step explanation:

We are given;

there are 3 different math courses, 3 different science courses, and 5 different history courses.

Thus;

Number ways to take math course = 3

The number of ways to take science course = 3

The number of ways to take history course = 5

Now, if a student must take one of each course, the different ways it can be done is;

possible ways = 3 x 3 x 5 = 45 ways.

Thus, number of different ways in which a student must take one of each subject is 45 ways.

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

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step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )