In a study of 225 adults, the mean heart rate was 72 beats per minute. assume the population of heart rates is known to be approximately normal with a standard deviation of 10 beats per minute. what is the 90% confidence interval for the mean beats per minute?

Confidence interval lower bound = 72-1.097 = 70.903

                                Upper bound = 72+1.097=73.097

Step-by-step explanation:

In a study of 225 adults, the mean heart rate was 72 beats per minute

Hence sample size n = 225

sigma = population std deviation = 10

Sample std deviation = 10/sqrt 225 = 0.67

Since n is sufficiently large we can use Z critical value for finding confidence interval 90%

Two tailed z critical for 90% is 1.645

Margin of error = 1.645 *0.67=1.097

Confidence interval lower bound = 72-1.097 = 70.903

                                Upper bound = 72+1.097=73.097

step-by-step explanation:

quartic functions has x = –1 and x = –2 as its only two real zeroes:

f(x) = a(x+2)(x+1)   a: real number

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