The average score of local students on a college entrance exam is 110 with standard deviation of 15. The distribution is roughly bell-shaped. What is the percentage of local student with score below 95? Use the empirical rule to find the following percentage. A. 34%
B. 16%
C. 15.5%
D. 13.5%

B

Step-by-step explanation:

Here, we want to use the empirical rule to find the percentage.

The first thing we will do here is to find the z-score

Mathematically;

z-score = (x -mean)/SD

from the question, x = 95, mean = 110

and SD = 15

So z-score will be ;

(95-110)/15 = -15/15 = -1

So the probability we want to calculate is;

P(z < -1)

In terms of the empirical rule, we want to find the proportion of the scores which is less than 1 standard deviation of the mean.

According to the empirical rule, the proportion which is less than 1 standard deviation below the mean is 15.866% and the closest answer to this is 16% which is option B

By definition, the empirical rule is basically used in finding the proportion of values in this case scores which are at a certain standard deviation value below or above the mean. Below the mean are represented as negatives while above the mean are represented as positives.

c is the correct answer

step-by-step explanation:

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)