It takes a car a certain amount of distance to stop, depending on its speed. The equation d = 0.05s2 + 1.1s models that, with d being the distance, in
feet, it takes to stop and s is the speed, in miles per hour. If someone's car
stops after 300 feet in a highway with a speed limit of 55 mph, was that car
speeding?

the reason why your question keeps getting deleted because this is not a school related question : )

i will answer your question though.

i never tried church's

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3