Pack-Em-In Real Estate is building a new housing development. The more houses it builds, the less people will be willing to pay, due to the crowding and smaller lot sizes. In fact, if it builds 40 houses in this particular development, it can sell them for $200,000 each, but if it builds 60 houses, it will only be able to get $160,000 each. Obtain a linear demand equation and hence determine how many houses Pack- Em-In should build to get the largest revenue. What is the largest possible revenue?

Using a linear and a quadratic function, it is found that the largest possible revenue is of $9,800,000.

The demand function has a linear format, given by:

In which:

40 houses can be sold for $200,000 each, thus, the first point of the linear function is: (40, 200000).

60 houses can be sold for $160,000 each, thus, the second point is: (60, 160000).

The slope is given by change in the output divided by change in the input, thus:

Thus:

Point (40, 200000) means that when . This is used to find b.

Then

The revenue function is:

It is a quadratic equation with

Since the quadratic equation is concave down, the maximum value is:

The largest possible revenue is of $9,800,000.

A similar problem is given at link

answer: the area of the parallelogram below is 42 square meters.

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b

step-by-step explanation:

the total is 23.97. 0.25% is off so you have to subtracting 25% from 100% and you will get 75% if you convert it to decimal you will get 0.75. you have to find the original because the formula is % times original = total.so you have the total and the % so you just have to plug it in.