As a motorcycle accelerates at 5.1 m/s2, its speed changes from 16 km/h to 118 km/h. how long does this take?

Acceleration (a) = 5.1 m/s²
Initial speed (u) = 16 km/h ⇒ m/s ≈ 4.5m/s
Final speed (v) =118 km/h ⇒  m/s ≈ 32.8m/s

Distance(S) travel in that particular instant is carried out by 'Third equation of motion' i.e., v² = u² + 2aS

So, When all quantities are in S.I. unit then,
putting the values in the equation of motion,

As we have to carry out the distance covered,
2·a·S = v² - u²
S = 
Putting values in derived equation,
⇒ S = 
⇒ S = 
⇒ S = 
⇒ S ≈ 103.489 m

The total distance covered in that given condition is approx. 103.289 m.

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