HEL PLEASEEE Passing through (-1, -2) and perpendicular to the line whose equation is y + 6 =4/5 (x-5) write an equation in slope intercept form

y = - x -

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

y + 6 = (x - 5) ← is in point- slope form

with slope m =

Given a line with slope m then the slope of a line perpendicular to it is

= - = - = -

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - , thus

y = - x + c ← is the partial equation

To find c substitute (- 1, - 2) into the partial equation

- 2 = + c ⇒ c = - 2 - = -

y = - x - ← equation of perpendicular line

Step-by-step explanation:

Hey there!

Given,

The line is passing through point (-1,-2) and perpendicular to the line (y+6) = 4/5(x-5).

Now,

The equation of a st.line passing through point (-1,-2) is,

Put all values.

It is the 1st equation.

Another equation is (y+6)= 4/5(x-5).

From equation (ii) {After comparing the equation with y =mx+c}.

We get,

M2= 4/5.

Now,

As per the condition of perpendicular lines,

m1×m2= -1.

Simplify them to get answer.

Therefore the slope is, -5/4.

Now, keep the slope in 1st equation.

Simplify them to get answer.

Therefore the required equation is y = -5/4x -13/2.

Hopeit helps....

step-by-step explanation:

compare

these sign is used to tell weather the number is greater or less than the number   <   or >     but this sign means its equal =    

hope this you and

step-by-step explanation: