find the base of isolation triangle whose area is 60 CM square and length of one of its equal side is 13 cm

base = 10 cm

Step-by-step explanation:

The height from the vertex is a perpendicular bisector of the isosceles Δ

This line divides the triangle into 2 right triangles with hypotenuse 13

Thus each right triangle is a 5- 12- 13 with legs 5 and 12

The height is 12 cm and the base 5 cm

Then the base of the isosceles Δ = 2 × 5 cm = 10 cm

Note Area = 0.5 × 10 × 12 = 60 cm²

3x + 18 = 147°

step-by-step explanation:

3x + 18 = 147°, because the value of the central angle is equal to the value of the arc formed by it.

i hope i you.