F(r)=(r-14)^2-56.25f(r)=(r−14) 2 −56.25f, left parenthesis, r, right parenthesis, equals, left parenthesis, r, minus, 14, right parenthesis, squared, minus, 56, point, 25 1) What are the zeros of the function? Write the smaller rrr first, and the larger rrr second. \text{smaller }r=smaller r=start text, s, m, a, l, l, e, r, space, end text, r, equals \text{larger }r=larger r=start text, l, a, r, g, e, r, space, end text, r, equals 2) What is the vertex of the parabola?

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

y=mx+

no this is a nonlinear negative

what are you trying to solve here

step-by-step explanation: