(3y + 2)(7y) y= 1
How do I evaluate that. Please show work

17

Step-by-step explanation:

y= 1

(3y + 2)(7y)                

(3(1) + 2(7(1))              Replace y with given number

(3 + 2(7))                    Multiply 1 to 3 and 7

(3 + 14)                       Multiply 2 and 7

(17)                              Add 3 and 14

1.  y = 1/7 = 0.143

2.  y = 2/3 = 0.667

Step-by-step explanation:

STEP  1 :

Equation at the end of step 1

 (3y - 2) • (7y - 1)  = 0  

STEP  2 :

Theory - Roots of a product

2.1    A product of several terms equals zero.  

When a product of two or more terms equals zero, then at least one of the terms must be zero.  

We shall now solve each term = 0 separately  

In other words, we are going to solve as many equations as there are terms in the product  

Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation:

2.2      Solve  :    3y-2 = 0  

Add  2  to both sides of the equation :  

                     3y = 2

Divide both sides of the equation by 3:

                    y = 2/3 = 0.667

Solving a Single Variable Equation:

2.3      Solve  :    7y-1 = 0  

Add  1  to both sides of the equation :  

                     7y = 1

Divide both sides of the equation by 7:

                    y = 1/7 = 0.143

answer: im gonna go with milli

step-by-step explanation: