Please post in the discussion below a solution for each region. To be clear, your post should give a number for Region A, a different number for Region B, a third number for Region C, and a fourth number for Region D. If you believe that there is no number possible for a Region, please explain why. After your initial post, read and comment on someone else's solution. If you believe their solution to be inaccurate or incomplete, explain why. If you believe their solution to be complete, comment on their explanation and what specifically they said that helped you understand their solution better.

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

1. 3. can also be expressed as (22/7)

2. -4.5

3. 3.6

happy to

pls mark as brainliest

step-by-step explanation:

1. perpendicular

2. parallel

3. perpendicular