Mathematics, 24.09.2020 14:01 adrian128383
How can (a+3)2=a2+6a+9 be derived from the polynomial identity (a−3)2=a2−6a+9?
Add 12a to both sides of (a−3)2=a2−6a+9.
Substitute −a for a on both sides of (a−3)2=a2−6a+9.
Multiply both sides of (a−3)2=a2−6a+9 by −1.
Add 6 to both sides of (a−3)2=a2−6a+9.
Answers: 3
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How can (a+3)2=a2+6a+9 be derived from the polynomial identity (a−3)2=a2−6a+9?
Add 12a to both side...
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