A rectangle has an area of 120 square cm. Its length and width are whole numbers. List the possible dimensions of the rectangle. Which possibility gives the smallest perimeter?

kindly check explanation

Step-by-step explanation:

Given that:

Area of rectangle = 120 cm²

Assume ; Length and width are whole numbers

Possible dimension of the rectangle will be :

Area of a rectangle = Length × width

Area = 120cm²

Possible dimensions :

80cm by 1 cm

40cm by 2cm

20cm by 4cm

10cm by 8cm

5cm by 16cm

Possibility which gives the smallest perimeter :

Dimension = 10cm by 8cm

Perimeter of Rectangle = 2(length + width)

Perimeter of Rectangle :

= 2(10 + 8)cm

= 2(18)cm

= 36cm

5

step-by-step explanation:

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb