Corinne and Aretha are having a 26-mile race. Corinne gave Aretha a head start by letting her begin 3.5 miles in front of the start line. Their distances past the start line as the race has progressed can be represented by linear functions and are shown in the table and graph below. How many minutes after the start of the race will Corinne catch Aretha? Corinne’s Distance Past the Start Line
Time (minutes)
10
20
30
40
50
Distance (miles)
1.25
2.5
3.75
5.0
6.25

A graph titled Aretha's Distance Past the Start Line has time (minutes) on the x-axis and Distance (miles) on the y-axis. A line goes through points (10, 4.5), (20, 5.5), (30, 6.5), (40, 7.5), and (50, 8.5).
140 minutes
180 minutes
208 minutes
225 minutes

A. 140 minutes

Step-by-step explanation:

I took the test

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3