A is the event that a policyhol der is classified as low-risk. B is the event that a policyholder suffered a loss. The probability that a low risk policyholder suffered a loss is 15%. The probability that a policyholder who suffered a loss is low-risk is 5%. Which of the following equals the probability of the intersection of A and B? A) 0.05 Pr A)
B) 0.15 Pr (B)
C) 0.2 Pr (A UB)
D) 3/83 Pr (AUB)
E) 3/77ET Pr A UB)

B) 0.15 Pr (B)

Step-by-step explanation:

A is the event that a policyholder is classified as low-risk.

B is the event that a policyholder suffered a loss.

P(A∩B) is the probability that a low risk policyholder suffered a loss is 15%.

P(A∩B)= 15%= 15/100= 0.15

P(B∩A) is the  probability that a policyholder who suffered a loss is low-risk is = 5%= 5/100= 0.05

Intersection means finding those elements which are common to both sets. Now we have to find those elements of A which are common to B. This is already given in the statement above and is 15 %.

Hence

P(A∩B)= 15%= 15/100= 0.15

Choice B is the correct answer.

-7

step-by-step explanation:

x^2 + 18x + 74 = (x + 9)^2 - 81 + 74

= (x + 9)^2 - 7.

so q = -7.

deez nu tz

step-by-step explanation: