On a map, a hospital is located at (-42,7). A wreck occurs at (13,-14). How far must the Air Care helicopter fly to reach the wreck from the hospital. (Each unit on the map equals one mile.)

The helicopter must cover a straight line distance of approximately 61.270 miles from the hospital to the wreck site.

Step-by-step explanation:

Let suppose that Air Care helicopter travels in straight line from the hospital to the wreck site, we can determine that distance (), measured in miles, by using the following Pythagorean identity from Analytical Geometry:

Where:

, - Location of the wreck site, measured in miles.

, - Location of the hospital, measured in miles.

If the location of the wreck site and the hospital are and , respectively. The distance that helicopter must cover is:

The helicopter must cover a straight line distance of approximately 61.270 miles from the hospital to the wreck site.

d

step-by-step explanation:

by observation, we can see that the the graph is simply the graph of y = |x| that has been shifted 4 units downwards and 3 units to the left.

we can recognize in choice d :

y = | x + 3 |   - 4 (rewriting in general form)

y = | x - (- 3) |   - 4

the "-4 " term means   that the graph has been shifted by 4 units in the negative y direction

the "-3 " term means   that the graph has been shifted by 3 units in the negative x direction

this matches our observation of the graph described above.

he sells x mount because thats eqivilqant to the maz and then divided into quarters

step-by-step explanation: