You order 1.5 pounds of turkey at the deli. You will accept the turkey if its weight is between 1.54 and 1.46 pounds. What absolute value inequality can be used to describe the tolerance of the weight of the turkey?

Given:

You order 1.5 pounds of turkey at the deli. You will accept the turkey if its weight is between 1.54 and 1.46 pounds.

To find:

The absolute value inequality that can be used to describe the tolerance of the weight of the turkey

Solution:

Let x be the actual weight of the turkey.

It will accepted, if its weight is between 1.54 and 1.46 pounds.

Subtract 1.5 from each side.

Therefore, the required absolute inequality is .

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.

connie < felicia < stew

step-by-step explanation:

stew:

we need to find the slope

m = (y2-y1)/ (x2-x1)

    = (2650-795)/(10-3)

    = 1855/7

265 words per minute

connie:

we need to find the slope

m = (y2-y1)/ (x2-x1)

we have two points (0,0) and (4,800)

m = (800-0)/(4-0)

  m = 800/4

    200 words per minute

felicia:

260 words per minute

200< 260 < 265

connie < felicia < stew