Shawn gets an allowance of $5 every other Sunday for doing chores. He likes to stop on his way home from school and buy a healthy snack. His favorite treat costs $0.65. How many of these snacks can Shawn afford every two weeks? After buying as many of these snacks with his $5 as possible, Shawn puts his left-over allowance in his piggy bank. He is saving to buy a new calculator. The model he wants costs $8.95. (It performs integer division and operations with fractions!) How many weeks will it take Shawn to save enough for the calculator?

Shawn can 7 of these snacks. The total comes out to be $4.55. So he will have 45 cents left over to save for his calculator. It will take 40 weeks to get $8.95 for Shawn's calulator.  .45 x 20 = $9.00 And he will have 5 cents left over.

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1