The distance between 2 trees is 11 meters. The first tree is 12 meters and the second tree is 29 meters. What is the distance between the tops of the trees?

Form a right triangle, with the base being the distance between the trees, 11 meters.

The height would be the difference between the height of the two trees: 29-12 = 17 meters

Now using the Pythagorean theorem calculate the hypotenuse, which would be the distance between the tops:

X ^2 = 11^2 + 17^2

X^2 = 121+ 289

X^2 = 410

X = sqrt(410)

X = 20.24845

The distance is:

Exact answer = sqrt(410) meters

Decimal answer = 20.24845 meters (round the answer as needed)

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)

can you make your screen more see able?

then i might be able to .