Arobot is at position A(30,40) and is heading toward the point B (1000, 1000) along a straight line at a constant speed. The robot will reach point B in 10 hours.

What is the location of the robot at the end of the fourth hour?

(418, 424)

Step-by-step explanation:

Arobot travels at constant speed. The total trip takes 10 hours. We want to know its position is 4 hours. The fraction of the path it will travel in 4 hours is 4/10 of the entire path. We need to find what point is 4/10 of the way from point A to point B.

For each coordinate, we find 4/10 of the difference between point A and B, and we add it tot eh coordinate of point A.

x-coordinate:

difference in x-coordinates: 1000 - 30 = 970

4/10 * 970 = 388

30 + 388 = 418

The x-coordinate is 418

y-coordinate:

difference in x-coordinates: 1000 - 40 = 960

4/10 * 960 = 384

40 + 384 = 424

The x-coordinate is 424

(418, 424)

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

a)(x-2)^2+(y-1)^2=9

step-by-step explanation:

(picture explains)