Which is a counterexample for the conditional statement shown? If the numerator of a fraction is larger than the denominator of the fraction, then the fraction is greater than 1.
any fraction with a denominator of O
any fraction with a numerator of O
any fraction with a positive numerator and a negative denominator
any fraction with a negative numerator and a positive denominator

Any fraction with a positive numerator and a negative denominator

Step-by-step explanation:

A counterexample in math refers to when a condition is satisfied but the result is not the conclusion that the statement said it would lead to.

In this instance, the statement is that if the numerator of the fraction is larger than the denominator, the result will be greater than 1.

If the numerator is positive and the denominator is negative then the numerator is larger than the denominator because all positive numbers are larger than negative numbers on the number line. However, the result will always be less than 1.

For instance, take the following fractions;

In each case the numerator was larger than the denominator but the result was always less than 1.

the answer is c.

for continuous functions, they continue in the same pattern and you have to find that pattern kinda like slope

126.66 m²

step-by-step explanation:

the pertinent area formula is a = πr², where r is the radius.

here, a = π(6.35 m)² = 40.32π, or approximately 126.66 m²