Suppose a rocket is launched from a launching platform and travels directly upward at a constant speed of 16 feet per second. The rocket is 80 feet above the ground 2 seconds after it was launched. Write a formula that expresses the rocket's height above the ground in feet,
h, in terms of the number of seconds t since the rocket was launched.

your answer is 23/2 - 13.5

step-by-step explanation:

7/2 evaluates to

multiply x and 4.5

multiply x and 1

the x just gets copied along.

the answer is x

x

4.5*x evaluates to 4.5x

multiply 3 and 4.5x

multiply 1 and x

the x just gets copied along.

x

4.5*x*3 evaluates to 13.5x

7/2-4.5*x*3 evaluates to

  + 8 =

the answer is

7/2-4.5*x*3+8 evaluates to

17   x 256=4352

sorry if this is wrong, i'm new.

step-by-step explanation: