1/3D + 10 = 3/5 d
Solve pls

1/3D + 10 = 3/5D

10 = 3/5 D ÷ 1/3 D

10 = 3D/5 ÷ D/3

10 = 3D/5 × 3/D

(btw there is no cross cancleing, just straight up multiply.)

next

10 = 9D/5D

cancel the 10 and 5D to make 10 to 2, and 5d to D.

Next, cancel both the D's (the 9d and the d (the d becomes 1 which is  just 9 over nothing. translates to just a simple 9.))

there is a 2 on the opposite side of the 9, so bring it under 9. so 9/2

then divide to get 4.5

4.5 is the answer!

Mark me brainliest if it is correct!

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.

b. x- 48 =120

step-by-step explanation: