what is an equation of the line that passes through the point (6,-2) and is perpendicular to the line 6x+y=2

We want to find a line such that it passes through a given point and is perpendicular to another line.

We will find that the equation of the line is: y = (1/6)*x - 3

First, we do know that for a line of the form:

y = a*x + b

where a is the slope and b is the y-intercept.

Any perpendicular line will have a slope equal to the opposite of the inverse, so the slope of the perpendicular line will be: -(1/a).

Now we want to find a perpendicular line to:

6*x + y  = 2

We rewrite it in the slope-intercept form:

y = -6*x + 2

The slope is -6, then the slope of a perpendicular line will be:

-(1/-6) = (1/6)

Then the general perpendicular line is:

y = (1/6)*x + b

To find the value of b, we use the fact that our line must pass through the point (6, -2). This means that when x = 6, y = -2

Repacing that in the equation we get:

-2 = (1/6)*6 + b

-2 = 1 + b

-2 - 1 = -3 = b

Then the equation of the line is:

y = (1/6)*x - 3

If you want to learn more, you can read:

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Step-by-step explanation:

y = -6x + 2

perp. 1/6

y + 2 = 1/6(x - 6)

y + 2 = 1/6x - 1

y = 1/6x - 3

u what ?

step-by-step explanation:

after 1 year: 221 deer

step-by-step explanation:

30% of 170 is 51. 170+51=221