What is the equation of a line that has a slope of 2 and passes through the point (-6, 3)?

y=2x+15

Step-by-step explanation:

Idk if you still need help but this is the answer.

Explanation:

You want to find the equation for a line that passes through the point (-6,3) and has a slope of 2.

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

To start, you know what m is; it's just the slope, which you said was 2. So you can right away fill in the equation for a line somewhat to read:

y=2x+b.

Now, what about b, the y-intercept?

To find b, think about what your (x,y) point means:

(-6,3). When x of the line is -6, y of the line must be 3.

Because you said the line passes through this point, right?

Now, look at our line's equation so far: . b is what we want, the 2 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (-6,3).

So, why not plug in for x the number -6 and for y the number 3? This will allow us to solve for b for the particular line that passes through the point you gave!.

(-6,3). y=mx+b or 3=2 × -6+b, or solving for b: b=3-(2)(-6). b=15.

The equation of the line that passes through the point (-6,3) with a slope of 2

is y=2x+15

< 4, -5>

step-by-step explanation:

starting from g. we move 4 right and then 5 down to get to h. that means the vector is < 4, -5>