1) 4y - 7+ 2y = -3/4 - 1)-1 2) -(5a + 6) = 2(3a + 8)

3) -8x - (3x + 6) = 4 - X

4) 14 + 3n = 8n - 3(n - 4)

5) 6.8 - 4.2b = 5.6b - 3

6) 1—3+2–3m=2–3M-2–3

7) 1 — 3(t + 6) -10 = -3t+2

8) 1-2r+6 = 3 - 2r

The sum of the first eight terms of an arithmetic progression is 9m + 14. the fifth term of the06 progression is 2m - 6, where m is a constant.given that the first term of the progression is 26,find the value of the common difference, d and thevalue of m.