The line contains the point (-4,-4) and is perpendicular to a line with a slope of 5/2 . The equation is this line is ?

2x + 5y + 28 = 0

Step-by-step explanation:

since they are perpendicular,

m1 ×m2 = -1

5/2 × m2 = -1

m2 = -2/5

now,

y -y1 = M (x-x1)

y - (-4) = -2/5 ( x - (-4) )

y +4 = -2/5 ( x + 4 )

5 ( y +4 ) = -2 ( x+4)

5y +20 = -2x - 8

2x + 5y +20 + 8 =0

2x + 5y + 28 = 0

f(x) is the value of the function. b is the value of the function when x equals zero or the y-coordinate of the point where the line crosses the y-axis in the coordinate plane.

step-by-step explanation:

hope this !