Graph the line passing through (−2,5) whose slope is m=1/5

Hello there! :)

Given:

x-coordinate of point = -2

y-coordinate of point = 5

Slope, or "m" = 1/5

Substitute in these values into slope-intercept formula (y = mx+b)

5 = 1/5(-2) + b

5 = -2/5 + b

25/5 = -2/5 + b

27/5 = b

Rewrite the equation:

y = 1/5x + 27/5

Graph the equation using a graphing utility:

In order to graph the line, you need to first find the y-intercept (aka 'b').

Equation: y=mx+b

Given the two points and slope, we can plug in and find for b

5 = 1/5(-2) + b

5 = -2/5 + b

b = 5 + 2/5

b = 27/5 or 5.4

So your final equation will be: y=1/5x+27/5

Lastly you just need to plot the 'b = 5.4'  on the y-axis and place the slope as 1 over 5.

according to the triangle sum theorem, all the angles in a triangle must add up to 180 degrees. if we know one angle is already 90, we do 180-90=90. the other 2 angles must add up to 90, exactly.

step-by-step explanation:

1 + (6 / x - 1)

step-by-step explanation:

divide using polynomial division.